2t^2+12t+18=8t

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Solution for 2t^2+12t+18=8t equation: 



2t^2+12t+18=8t

We move all terms to the left:

2t^2+12t+18-(8t)=0

We add all the numbers together, and all the variables

2t^2+4t+18=0

a = 2; b = 4; c = +18;
Δ = b2-4ac
Δ = 42-4·2·18
Δ = -128
Delta is less than zero, so there is no solution for the equation

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